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Power Electronics

Buck Converter (Step-Down)

The crude way to get 5 V from 12 V is to burn the difference as heat (a linear regulator — 40% efficiency). The buck is the elegant way: it switches the voltage on and off rapidly and takes the average; ideally it produces no heat at all, with efficiency of 90%+.

Its secret is the inertia of the inductor: while the switch is on, the source feeds the load through the inductor and the inductor "stockpiles" current; when the switch turns off, the inductor refuses to stop — it keeps driving its current through the diode path. The load never notices the interruption. The average output depends only on the ratio: Vout = D · Vin.

The ripple in the inductor current is ΔIL = (Vin−Vout)·D/(f·L); the output capacitor smooths the rest. Raising the frequency shrinks L and C but creates switching losses — design is always this balance.

Formulas

Vout = D · Vin (continuous conduction)
ΔIL = (Vin − Vout) · D / (f · L)
Efficiency = P_load / P_source

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Test Yourself

What duty cycle is roughly needed for an 8 V output from a 24 V input?
Answer: 33% — D = Vout/Vin = 8/24 ≈ 33%.
In a buck converter, through which path does the inductor current continue while the switch is off?
Answer: Through the (freewheel) diode — Inductor current is continuous; during off-time the freewheel diode closes the loop.